if x^2-1 is a factor of ax^3+bx^2+cx+d, show that a+c=0.
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Given:-
- f(x) = ax³ + bx² + cx + d
- (x² - 1) is a factor of f(x)
To prove:-
- a + c = 0
Solution:-
We have, x² - 1 = 0
So, x² = 1
→ x = ± 1
★ Put x = -1 :-
→ a(-1)³ + b(-1)² + c(-1) + d = 0
→ - a + b - c + d = 0 ---(1)
★ Now, Put x = 1 :-
→ a(1)³ + b(1)² + c(1) + d = 0
→ a + b + c + d = 0 ---(2)
★ Substract eq(2) from eq(1) :-
Then we get,
→ - 2a - 2c = 0
→ - 2(a + c) = 0
→ a + c = 0
★ Hence, SolvEd!!!
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