Math, asked by joshikasriramprabhu, 10 months ago

if x^2 +1/x^2=1 , then 1+x^6=​

Answers

Answered by NitishGummadavelly
0

Answer:

-2

Step-by-step explanation:

we know that

(a+b)^3 = a^3 + 3ab(a+b) + b^3

so cubing on both sides for eqn

x^2 +1/x^2=1 we get

x^6+3*x^6*1/x^6(x^2+1/x^2)+1/x^6=1

x^6+3(1)+1/x^6 = 1

x^6+1/x^6=1-3

x^6+1/x^6=-2

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