if x^2+1/x^2=123, find the value of x^3-1/x^3.
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x²+1/x²=123
then x²+1/x²-2=121
(x-1/x)²= 121
(x-1/x)=√121=11
x³-1/x³= (x-1/x)(x²+1/x²+[x * 1/x ]
x³-1/x³= 11(123+1) = 11×124= 1364
hope this helps
then x²+1/x²-2=121
(x-1/x)²= 121
(x-1/x)=√121=11
x³-1/x³= (x-1/x)(x²+1/x²+[x * 1/x ]
x³-1/x³= 11(123+1) = 11×124= 1364
hope this helps
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