If (x)^2 - (1/x)^2 = 15/4, then (x)^3 - ( 1/x )^3 = ?
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HEYA ❕ HERE'S YOUR ANSWER
X² + 1/x² = 14
(x + 1/x)² -2.x.1/x = 14
(x + 1/x )² -2 = 14
(x + 1/x )² = 16
take square root both sides
(x + 1/x) = 4
then,
x³ + 1/x³ = ( x + 1/x)³ - 3.x.1/x(x + 1/x)
= ( x +1/x)³ -3(x + 1/x)
= (4)³ -3(4)
= 64 - 12
= 52
HOPE IT HELPS YOU
X² + 1/x² = 14
(x + 1/x)² -2.x.1/x = 14
(x + 1/x )² -2 = 14
(x + 1/x )² = 16
take square root both sides
(x + 1/x) = 4
then,
x³ + 1/x³ = ( x + 1/x)³ - 3.x.1/x(x + 1/x)
= ( x +1/x)³ -3(x + 1/x)
= (4)³ -3(4)
= 64 - 12
= 52
HOPE IT HELPS YOU
ashmitkumar2:
how did you solve this?
see question again
Answered by
0
hey dude it's simple
see the attachment
hope it helps you
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