if x^2+1/x^2=18,find x-1/x and x+1/x?
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Answer:
x^2+1/x^2=18
(x+1/x)^2-2.x.1/x=18
(x+1/x)^2-2=18
(x+1/x)^2=18+2=20
x+1/x=√20=2√5
again,
x^2+1/x^2=18
(x-1/x)^2+2.x.1/x=18
(x-1/x)^2=18-2=16
x-1/x=√16=4
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