If x^2+1/x^2=18 then find the value of x^3-1/x^3
Answers
Answered by
12
x^2+ 1/x^2=18
x^2+1/x^2 -2=18-2
(x-1/x)^2=1886
(x-1/x)=4
x^3-1/x^3
=(x-1/x)(x^2+1/x^2+2)
=4×(18+2)
=4×20
=80
x^2+1/x^2 -2=18-2
(x-1/x)^2=1886
(x-1/x)=4
x^3-1/x^3
=(x-1/x)(x^2+1/x^2+2)
=4×(18+2)
=4×20
=80
Answered by
9
x² + 1/x² = 18.
x² + 1/x² - 2 = 18 - 2.
(x-1/x)² = 1886.
(x-1/x) = 4.
After That,
x³ - 1/x³.
= (x-1/x)(x²+1/x²+2).
= 4×(18+2).
= 4×20.
= 80.
x² + 1/x² - 2 = 18 - 2.
(x-1/x)² = 1886.
(x-1/x) = 4.
After That,
x³ - 1/x³.
= (x-1/x)(x²+1/x²+2).
= 4×(18+2).
= 4×20.
= 80.
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