If x^2+1/x^2=1then the value of x^3+1/x^3is
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Answer:
x³+1/x³ = 0
It is given that,
x²+1/x² = 1 ---(1)
=> x² + 1/x² +2 = 1 + 2
=> ( x + 1/x )² = 3
=> (x+1/x ) = ± √3 ----(2)
Now ,
x³+1/x³
= (x+1/x)³ -3(x+1/x)
Case - 1
If x +1/x = √3
then
x³+1/x³ = (√3)³ -3×√3
= 3√3-3√3
= 0
Case - 2
if x+1/x = -√3
then
x³+1/x³
= (-√3)³ - 3(-√3)
= -3√3 + 3√3
= 0
••••
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