if x^2+1/x^2=2 find x+1/x and x-1/x. Hence find also x^2 -1/x^2
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Answered by
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Step-by-step explanation:
Correct option is
A
-1
C
1
D
2
sin
−1
(x
2
+x+1)+cos
−1
(ax+1)=
2
π
cos
−1
(ax+1)=
2
π
−sin
−1
(x
2
+x+1)
cos
−1
(ax+1)=cos
−1
(x
2
+x+1)
x
2
+x+1−ax−1=0
x
2
+x(1−a)=0
x=
2
a−1±(1−a)
Therefore
x=0 and x=(a−1)
Also −1≤ax+1≤1
a
−2
≤x≤0
Clearly a cannot be 1 as we would get coincident values of x.
If a=-1, x=-2 then
cos
−1
(2+1)
cos
−1
(3) does not exists.
If a=2, x=1
sin
−1
(x
2
+x+1)
=sin
−1
(3)
Which does not exists.
Hence only a=0 and x=−1 satisfies the above equation.
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