Question

if x^2-1÷x^2=2 then x-1÷x=?





plzzzz give me answer guys!​

Answer 1

$\red {\underline{\underline {Answer:}}}$

$\sqrt{ 2\sqrt{2} - 2}$

$\red {\underline{\underline {Step-by-step\: explanation:}}}$

${x}^{2} - \frac{1}{ {x}^{2} } = 2 \\ or, \: ( {x}^{2} - \frac{1}{ {x}^{2} } ) ^{2} = {2}^{2} \\ or, \: ( {x}^{2} + \frac{1}{ {x}^{2} } )^{2} - 4 \times {x }^{2} \times \frac{1}{ {x}^{2} } = 4 \\or, \: {( {x}^{2} + \frac{1}{ {x}^{2} } )}^{2} - 4 = 4 \\ or, \: ({x}^{2} +\frac{1}{ {x}^{2} } )^{2} = 4 + 4 \\or, \: ({x}^{2} + \frac{1}{ {x}^{2} } )^{2} = 8 \\ or, \: {x}^{2} + \frac{1}{ {x}^{2} } = \sqrt{8} \\ or, \: (x - \frac{1}{x})^{2} + 2 \times x \times \frac{1}{x} = \sqrt{8} \\ or, \: (x - \frac{1}{x} ) ^{2} + 2 = \sqrt{8} \\or, \: (x - \frac{1}{x} ) ^{2} = \sqrt{8 } - 2 \\or, \: x - \frac{1}{x} = \sqrt{2 \sqrt{2} - 2}$

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Answer 2

SORRY BRO I M UR SIS..●_●