If x^2 + 1/x^2 = 27 , find the value of x - 1/x
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xsq +1/x sq =27
(x-1/x)sq +2= 27
(x-1/x)sq = 25
x-1/x= 5 Ans
(x-1/x)sq +2= 27
(x-1/x)sq = 25
x-1/x= 5 Ans
Jack183739:
Sorry....I didn't understand
Ok ask ur doubt ?
First step which is applied is a formula of xsq +1/xsq
But (a+b)^2 = a^2 + b^2 + 2ab
Yh but here is asq + bsq
Not (a+b)whole sq
oooo.....thanks
Most wlcm...
Answered by
2
x^2+1/ x^ 2=27
x^2+1/x^2-2*x^2*1/x^2=25
(x-1/x)^2=(5)^2
x-1/x=5
x^2+1/x^2-2*x^2*1/x^2=25
(x-1/x)^2=(5)^2
x-1/x=5
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