if x^2+1/x^2=27 find the value of x-1/x
Answers
Answered by
9
Hii friend,
X²+1/X² = 27
X²+1 = 27X²
27X²-X² = 1
26X² = 1
X² = 1/26
X= ✓1/26
Therefore,
X-1/X = (✓1/26) - 1 / ✓1/26
= 1 - ✓26/✓26 / 1/✓26
= 1-✓26/1 = 1-✓26 Ans.
HOPE IT WILL HELP YOU..... :-)
X²+1/X² = 27
X²+1 = 27X²
27X²-X² = 1
26X² = 1
X² = 1/26
X= ✓1/26
Therefore,
X-1/X = (✓1/26) - 1 / ✓1/26
= 1 - ✓26/✓26 / 1/✓26
= 1-✓26/1 = 1-✓26 Ans.
HOPE IT WILL HELP YOU..... :-)
Rhidam:
hmm
Answered by
11
HERE'S YOUR ANSWER
x^2 + 1/x^2 = 27
Subtracting 2*x*1/x = 2 from both sides, we get
x^2 + 1/x^2 - 2*x*1/x = 27 - 2
(x)^2 + (1/x)^2 - 2(x)(1/x) = 25
We know that,
a^2 + b^2 - 2ab = (a - b)^2
So, (x - 1/x)^2 = 25
Therefore, (x - 1/x) = √(25) = 5.
HIPE HELPED!!
HAPPY TO HELP :)
x^2 + 1/x^2 = 27
Subtracting 2*x*1/x = 2 from both sides, we get
x^2 + 1/x^2 - 2*x*1/x = 27 - 2
(x)^2 + (1/x)^2 - 2(x)(1/x) = 25
We know that,
a^2 + b^2 - 2ab = (a - b)^2
So, (x - 1/x)^2 = 25
Therefore, (x - 1/x) = √(25) = 5.
HIPE HELPED!!
HAPPY TO HELP :)
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