Question

If x^2+(1/x^2)=27 find x+1/x

Answer 1

Answer:

$\frac{x^2+1}{x}$

Step-by-step explanation:

Answer 2

Answer:

The answer is $\sqrt {29}$

Step-by-step explanation:

Given  $\displaystyle x^2+\frac{1}{x^2}=27 ..(1)$

Using the identity $(a+b)^2=a^2+b^2+2ab$

      $\displaystyle \left(x+\frac{1}{x}\right)^2=x^2+\frac{1}{x^2}+2\times x\times \frac{1}{x}$

                       $=27+2=29$, using given result (1)

  $\displaystyle \Rightarrow x+\frac{1}{x}=\sqrt{29}$