Question

If x^2 + (1/x^2)=34,then find the value of 2(x+ 1/x^2) +6(x+ 1/x)+25

Answer 1

Answer:

Step-by-step explanation:

x^2+1/x^2=34

(x+1/x)^2 =x^2 +2+1/x^2

(x+1/x)^2 -2=x^2 +1/x^2 =34

(x+1/x)^2 =34+2=36

(x+1/x)=root of 36=6

so the value of x+1/x=6

2(34)+6(6)+25=68+36+25=129 is the answer