If x^2+1/x^2=34 then find value of x-1/x
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let x^2=t
then , t + 1/t =34
add 2 on both sides
t + 1/t +2 =34+2=36
(t + 1/t)^2 = t + 1/t +2
(t + 1/t)^2=(6)^2
t + 1/t = 6
t^2 + 1 -6t =0
t^2 - 3t -3t +1 =0
t(t-3)-1(t-3)=0
(t-1)(t-3) = 0
t=1 ; t=3
x^2 =1 ; x^2 =3
x= +1,-1 ; x= +sqrt.3 ,- sqrt.3
x-1/x ; x-1/x
= +1-1/1=0 ; = +sqrt.3-1/sqrt.3
= -1-1/1=-2 ; = -sqrt.3-1/-sqrt.3
Step-by-step explanatio
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