if ( x^2 + 1/x^2) =4 , find the values of ( x^2 + 1/x^2), ( x^4 + 1/x^4 )
Answers
Answer:
Value of x² + 1/x² is 4 and value of x^4 + 1/x^4 is 14
i.e.
x² + 1/x²=4
x^4 + 1/x^4=14
Step-by-step explanation:
x² + 1/x²=4
So x² + 1/x²=4
( x^4 + 1/x^4 ) =(x²)² + (1/x²)²
=(x² + 1/x²)²-2.x².1/x²
=4²-2 [Putting value of x² + 1/x²]
=16-2
=14
Ans:-Value of x² + 1/x² is 4 and value of x^4 + 1/x^4 is 14
Hope it helps you =)
Solution :-
→ (x² + 1/x²) = 4
squaring both sides we get,
→ (x² + 1/x²)² = (4)²
using (a + b)² = a² + b² + 2ab in LHS,
→ (x²)² + (1/x²)² + 2 * (x²) * (1/x²) = 16
→ x⁴ + 1/x⁴ + 2 = 16
→ (x⁴ + 1/x⁴) = 16 - 2
→ (x⁴ + 1/x⁴) = 14 (Ans.)
also, another values is same as given value .
Learn more :-
solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method
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