if x^2+1/x^2=51
find the value of
(x-1/x)
Answers
Answered by
15
x² + 1/x² = 51
On subtracting 2(x × 1/x ) from both sides, we get
x² + 1/x² - 2( x × 1/x ) = 51 - 2(x × 1/x )
( x - 1/x )² = 51 - 2
x - 1/x = √49
x - 1/x = 7
On subtracting 2(x × 1/x ) from both sides, we get
x² + 1/x² - 2( x × 1/x ) = 51 - 2(x × 1/x )
( x - 1/x )² = 51 - 2
x - 1/x = √49
x - 1/x = 7
Answered by
13
Hello dude !
♠ Here is your answer ♠
______________________________________________________________________________________
X² + 1/X² = 51
x² + 1/x² - 2(x×1/x) = 51
(x - 1/x)² = 49
x-1/x = ✓49 = 7 .
♥ Hope it helps ♥
♠ Here is your answer ♠
______________________________________________________________________________________
X² + 1/X² = 51
x² + 1/x² - 2(x×1/x) = 51
(x - 1/x)² = 49
x-1/x = ✓49 = 7 .
♥ Hope it helps ♥
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