Math, asked by samirkumargupta84, 10 months ago

If x^2+1/x^2 = 66, find the value of x-1/x .please solution this question.​

Answers

Answered by biligiri
0

Answer:

given x^2 + 1/x^2 = 66...........2

to evaluate x - 1/x

step 1 square x-1/x

=> (x-1/x)^2 = x^2 + 1/x^2 + 2*x*1/x

= 66 + 2

= 68 [ from 1 ]

therefore x - 1/x = √68 or 2√17

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