Question

if x^2+1/x^2=7 and x is not equal to 0 ; find the value of
7x^3+8x-7/x^3-8/x​

Answer 1

Answer:

the answer is 36√5

Step-by-step explanation:

7(x^3 - (1/x^3)) +8(x-(1/x))

(x-(1/x)){7(x^2+(1/x^2)-3)+8}

(√5)(36)