if x^2+1/x^2 = 7....
Find the values of
1. X+1/X
2. x - 1/X
3. 2x^2 - 2/x^2.
please help me ....
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Answered by
10
Step-by-step explanation:
Given : x² + 1/x² = 7
(i)
It can be written as,
⇒ x² + 1/x² = 9 - 2
⇒ x² + 1/x² + 2 = 9
⇒ (x + 1/x)² = 9
(x + 1/x) = ±3
(ii)
Given Equation can be written as,
x² + 1/x² = 5 + 2
⇒ x² + 1/x² - 2 = 5
⇒ (x - 1/x)² = 5
(x - 1/x) = ±√5
(iii)
x² - 1/x²
⇒ (x + 1/x)(x - 1/x)
⇒ (3)(√5)
⇒ 3√5
Then,
(2x² - 2/x²)
= 2(x² - 1/x²)
= 2(3√5)
= 6√5
Hope it helps!
Answered by
7
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