if x^2+1/x^2=7 then find value x^3+1/x^3
Answers
Answered by
0
Answer:
x^2+1/x^2 = 7
(x+1/x)^2-2 =7 [ (a^2+b^2) = (a+b)^2-2ab]
(x+1/x)^2 = 9
(x+1/x) = 3
x^3 +1/x^3 = (x+1/x) (x^2+1/x^2-1)
= 3(7-1). [a^3+b^3 = (a+b)(a^2+b^2-ab)]
= 3*6
= 18
HOPE IT HELPS YOU MARK IT AS BRAINLIEST
Answered by
0
Step-by-step explanation:
I hope the answer is satisfactory
Attachments:
Similar questions