if [x^2]+[1/x^2]=7 then [x]+[1/x ]= ?
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Answered by
2
Step-by-step explanation:
if x²+1/x²=7
then (x+1/x)²-2×x²×1/x²=7
or (x+1/x)²-2=7
or (x+1/x)²=7+2
or (x+1/x)²=9
or x+1/x= root 9
so x+1/x = 3
Answered by
1
Answer:
3
Explanation:
- (x+1/x)^2 = x^2 + 1/x^2+2*x*1/x
- (x+1/x)^2 = 7+2
- (x+1/x)^2 =9
- x+1/x = ✓9
- x+1/x =3
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