If x^2+1/x^2=79 , then find value of x+1/X
Answers
Answered by
210
We know that, (x + 1/x)^2 = x^2 + 1/x^2 + 2x + 1/x
Given , x^2 + 1/x^2 = 79
So, (x + 1/x)^2 = 79 + 2
(x + 1/x)^2 = 81
(x + 1/x ) = 9
Hope this helps!
Given , x^2 + 1/x^2 = 79
So, (x + 1/x)^2 = 79 + 2
(x + 1/x)^2 = 81
(x + 1/x ) = 9
Hope this helps!
Answered by
89
Answer:
Step-by-step explanation:
We know that, (x + 1/x)^2 = x^2 + 1/x^2 + 2x + 1/x
Given , x^2 + 1/x^2 = 79
So, (x + 1/x)^2 = 79 + 2
(x + 1/x)^2 = 81
(x + 1/x ) = 9
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