Math, asked by hjnnb6003, 7 months ago

If x^2+1/x^2=83,then find the value of x-1/x.

Answers

Answered by souravsarkar045
3

Answer:

Answer is 9.

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Step-by-step explanation:

Given,

 {x}^{2}  +  \frac{1}{ {x}^{2} }  = 83 \\  =  >  {(x -  \frac{1}{x} )}^{2}  + 2.x. \frac{1}{x}  = 83 \\  =  > {(x -  \frac{1}{x} )}^{2} + 2 = 83 \\  =  > {(x -  \frac{1}{x} )}^{2} = 83 - 2 \\  =  > {(x -  \frac{1}{x} )}^{2} = 81 \\  =  > x -  \frac{1}{x}  =  \sqrt{81}  \\  =  > x -  \frac{1}{x }  = 9

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