Question

if x^2+1/x^2=96 find x^3-1/x​

Answer 1

Answer:

Given x+y+z=12

Squaring it we get

x² + y² + z² + 2(xy + yz + zx)=144

Therefore xy + yz + zx=24

Also 1/x + 1/y + 1/z=36

Implies (xy + yz + zx)/xyz=36

⇒ xyz = (xy + yz + zx)/36 = 24/36 = 2/3

We know (x³ + y³ + z³) = (x + y + z)(x² + 2 y² + z² - xy - yz - zx) + 3xyz

3 x³ + y³ + z³ = (12) (9624) + 2 = 12 * 72 + Z

2 = 866

Answer 2

Step-by-step explanation:

if x^2+1/x^2=96 find x^3-1/x