Math, asked by BiswabrataSarkar, 8 months ago

if x^2+1/x=4; find the value of 2x^3+2/x^3​

Answers

Answered by akanshagarwal2005
4

Answer:

Given, (x^2+1)/x=4

=>x^2+1=4x

=>x^2–4x+1=0

=>x=2+root(3),2-root(3)

=>x^3=26+15root(3),14–9root(3)

The value of 2*x^3+(2/x^3) for x^3=26+15root(3) is 104

Answered by Anonymous
7

Step-by-step explanation:

x+1/x =4

squaring on both sides we get, x^2+1/x^2+2=16 => x^2+1/x^2=14

(x+1/x)^3= x^3+1/x^3+3(x*1/x)*(x+1/x)

64=x^3+1/x^3+3(4)

x^3+1/x^3=64–12=52

hence 2*x^3+2/x^3 =52*2=104

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