if x^2+1/x=4; find the value of 2x^3+2/x^3
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Answer:
Given, (x^2+1)/x=4
=>x^2+1=4x
=>x^2–4x+1=0
=>x=2+root(3),2-root(3)
=>x^3=26+15root(3),14–9root(3)
The value of 2*x^3+(2/x^3) for x^3=26+15root(3) is 104
Answered by
7
Step-by-step explanation:
x+1/x =4
squaring on both sides we get, x^2+1/x^2+2=16 => x^2+1/x^2=14
(x+1/x)^3= x^3+1/x^3+3(x*1/x)*(x+1/x)
64=x^3+1/x^3+3(4)
x^3+1/x^3=64–12=52
hence 2*x^3+2/x^3 =52*2=104
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