If (x^2+1)/x= 5/2 Find x^3-1/x^3
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Answer:
63/8(improper fraction) or 7 7/8(mixed fraction) or 7.875(decimals)
Step-by-step explanation:
(x^2 + 1)/x = 5/2
=> x + 1/x = 5/2
Squaring both sides,
=> (x + 1/x)^2 = (5/2)^2
=> x^2 + 1/x^2 + 2 = 25/4
=> x^2 + 1/x^2 + 2 - 4 = 25/4 - 4
=> x^2 + 1/x^2 - 2 = 9/4
=> (x - 1/x)^2 = 9/4
taking the square root on both sides,
=> x - 1/x = +/- 3/2
Cubing both sides,
=> (x - 1/x)^3 = (+/- 3/2)^3
=> x^3 - 1/x^3 - 3.x.1/x.(x-1/x) = +/- 27/8
=> x^3 - 1/x^3 - 3(+/- 3/2) = +/- 27/8
=> x^3 - 1/x^3 - (+/- 9/2) = +/- 27/8
=> x^3 - 1/x^3 = +/- 27/8 + (+/- 9/2)
=> x^3 - 1/x^3 = +/- (27/8 + 9/2)
=> x^3 - 1/x^3 = +/- 63/8 ... (answer)
Therefore, answer is 63/8(improper fraction) or 7 7/8(mixed fraction) or 7.875(decimals).
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