Question

if x^-2 = 125 then 1/x^3 + x^0 = ?​

Answer 1

Answer: 625√5 + 1.

Explanation:

x^-2 = 125

=> (x^-1)^2 = 125

=> x^-1 = 5√5

=> x = 1/(5√5).

Now,

1/x^3 + x^0

= 1/1/(5√5)^3 + 1 (as x^0 = 1 if x ≠ 0.)

= 625√5 + 1 (answer).

Answer 2

Step-by-step explanation:

Answer

Given, 5

3x−1

÷25=125

Since, 25=5×5=5

2

And 125=5×5×5=5

3

Therefore, 5

3x−1

÷(5)

2

=(5)

3

⇒(5)

3x−1−2

=(5)

3

[∵a

m

÷a

n

=(a)

m−n

]

⇒(5)

3x−3

=(5)

3

On comparing both sides, we get

⇒3x−3=3

⇒3x=6

⇒x=2