If x^2+14x=51 and x>0, what is the value of x+7?
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x^2+14x=51
x^2+17x-3x-51=0
x(x+17) - 3(x+17) =0
(x-3) (x+17) =0
x = 3 , -17
but x>0 , so x = -17 will be discarded.
so x = 3
x+7 = 3+7 = 10
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