Math, asked by sanjanadas1, 30 days ago

If x =2√15/√5+√3, find x+√3/x-√3 + x+√5/x-√5​

Answers

Answered by anujrouth
0

Answer:

2

Step-by-step explanation:

x+√3/x-√3    +    x+√5/x-√5

substitute the value of "x"

=> 2√15/√5+√3 +√3/2√15/√5+√3-√3          +        2√15/√5+√3+√5/2√15/√5+√3-√5

2√15+√15+3/√5+√3/2√15-√15-3/√5+√3 +  2√15+5+√15/√5+√3/2√15-5-            √15/√5+√3  

 

3√15+3/√15-3     +    3√15+5/√15-5

(√15-5)(3√15+3) + (√15-3)(3√15+5)/(√15-3)(√15-5)

45-15+3√15-15√15+45-15+5√15-9√15/30-5√15-3√15

60-16√15/30-8√15

2(30-8√15)/30-8√15

then the answer we get is        2      

Answered by mirzaaziz97017
0

Answer:

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