Question

if x^2 - 16x + 25 = 0 then find two values of x

Answer 1

x² - 16x + 25 = 0

We can find x value by completing square method,

x²-16x = -25
x²-2(x)(8) = -25

Adding (8)² on both sides,

x²-2(x)(8)+(8)² = -25 + (8)²
(x-8)² = -25 + 64
(x-8)² = 39
x-8 = ± √39

=> x = √39+8
=> x = -√39 + 8