Question

If x=2+2^1/3+2^2/3, find x^3-6x^2+6x

Answer 1

Hello Friend ✌
Here is u r Ans ➡

✨Given that x = 2 + 2^(2/3) + 2^(1/3)

so,

☄x - 2 = 2^(2/3) + 2^(1/3)

☄(x-2)^3 = [2^(2/3)+2^(1/3)]^3

✨using (a-b)^3= a^3 - b^3 - 3ab(a-b)

and (a+b)^3= a^3 + b^3 + 3ab(a+b) formulae.

or
x^3 - 8 - 6x(x-2) = 2^2 + 2^1 + 3*[2^{(2/3)+(1/3)}[2^(2/3)+2^(1/3)

✔or x^3 - 8 - 6x^2 + 12x = 4 + 2 + 6(x-2)

✔or x^3 - 8 -6x^2 + 12x = 6 + 6x - 12

✔or x^3 - 6x^2 +6x = 2

☄☄☄☄☄☄☄☄☄☄☄☄☄☄
Hope This Helps u ☺

Answer 2

Hey there !

It's the answer in given pic...

Thank you