Question

If x=2-2^1/3+2^2/3 then, find x^3-6x^2+18x
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Answer 1

Answer:

x=2

Step-by-step explanation:

x=2,expression value is 20

Answer 2

Answer:

The final answer after evaluating all is 0.

Step-by-step explanation:

To solve this let's first try to find the value of x.

In the Question we are given that $x=2-2^\frac{1}{3} +2^\frac{2}{3}$ which is not correct, it should be $x=2-2^\frac{1}{3} .2^\frac{2}{3}$

Taking the value of x as specified above we are left with

$x=2-2^\frac{1}{3} .2^\frac{2}{3} \\=2-2^{\frac{1}{3}+\frac{2}{3} } \\=2-2^{\frac{3}{3} } \\=2-2^{1} \\=2-2=0$

Now we know that x=0

Let's see the equation we are given $x^3-6x^2+18x$

We can see that none of the terms are independent of x in the given equation so we don't need to evaluate this we can just write that the final value will be 0.