if x^2+2= 2^(2/3) + 2^(-2/3) , show that 2x(x^2+3) =3
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Answer:
x^2-2=2^2/3+2^-2/3
x^2=2^2/3+2+2^-2/3
x^2=(2^1/3)^2 2^2/3 2^1/3 +(2^-1/3)^2
x^2=(2^1/3+ 2^-1/3)^2
[x= (2^1/3+ 2^-1/3)]
now use the value x in 2x^3+6x
then it come 5
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