If x=√2+√2+√2.....then x=?
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value of x = 2
I think your question is....
if x = √{2 + √{2 + √{2 + ........}}} then we have to find value of x.
√{2 + √{2 ........}} = x
[ there are infinite terms in the given expression. removing or adding one finite term into it, doesn't change its value. so, √{2 + √{2 ........}} = x also ]
now, x = √{2 + x}
now squaring both sides we get,
x² = 2 + x
x² - x - 2 = 0
x² - 2x + x - 2 = 0
x(x - 2) + 1(x - 2) = 0
(x + 1)(x - 2) = 0
x = 2, -1
but x = √{2 + √{2 + √{2 ........}} > 0
so, x ≠ -1 and hence x = 2
also read similar questions : 2^x + 2^x + 2^x = 192
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factorize
2x² - 6x² + x² - x + 2
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