If x-2=2,y-7=-12,3z=6,find the value of 3x2z+5y-18
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Given :-
x - 2 = 2
y - 7 = -12
3z = 6
Find, 3x²z + 5y - 18
Required solution :-
x - 2 = 2
Therefore, x = 2 + 2
x = 4
y - 7 = -12
Therefore, y = -12 + 7
y = -5
3z = 6
Therefore, z = 6/3
z = 2
Thus, x = 4, y = -5, z = 2
Now, 3x²z + 5y - 18
= 3(4)²(2) + 5 (-5) - 18
= 3(16) (2) + (-25) - 18
= 96 - 25 - 18
= 96 - 43
= 53
Hence, 53 is the required answer.
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