Math, asked by aryaamrita1985, 4 months ago

If x-2=2,y-7=-12,3z=6,find the value of 3x2z+5y-18​

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Answered by rajchoubey452
3

Answer:

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Answered by ItsBeautifulTimePass
8

Given :-

x - 2 = 2

y - 7 = -12

3z = 6

Find, 3x²z + 5y - 18

Required solution :-

x - 2 = 2

Therefore, x = 2 + 2

x = 4

y - 7 = -12

Therefore, y = -12 + 7

y = -5

3z = 6

Therefore, z = 6/3

z = 2

Thus, x = 4, y = -5, z = 2

Now, 3x²z + 5y - 18

= 3(4)²(2) + 5 (-5) - 18

= 3(16) (2) + (-25) - 18

= 96 - 25 - 18

= 96 - 43

= 53

Hence, 53 is the required answer.

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