Question

IF X^2+21X+104 =0 THEN X= ?

Answer 1

Answer to the question:

Given the equation,
x²+21x+104= 0
or, x²+(13+8)x+104= 0
or, x²+13x+8x+104= 0
or, x(x+13)+8(x+13)= 0
or, (x+13) (x+8)= 0
So we have found (x+13) = 0 and (x+8) = 0
Either,
x+13= 0 => x = -13 or x+8= 0 => x = -8
Hence, the value of x are -13 and -8

Answer 2

Heya

∆ Quadratic Equation ∆

${x}^{2} + 21x + 104 = 0$

$= > {x}^{2} + 13x + 8x + 104 = 0$

$= > (x + 13)(x + 8) = 0$

$= > (x + 13) = 0 \: \: or \: \: (x + 8) = 0$

$= > x = - 13 \: \: or \: \: - 8$

Hence, x has two possible values : ( -13 ) or ( -8 )