if x^2+2kx+4 has a root x=2,find the value of k
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Given that the equation x^2 + kx + 4 = 0 has a root x = 2.
Substituting the value of x in the given equation
( 2 )^2 + 2( 2 )k + 4 = 0
4 + 4 k + 4 = 0
4( 1 + k + 1 ) = 0
1 + 1 + k = 0
2 + k = 0
k = - 2
Therefore the value of k satisfying the equation is -2.
bans55:
Its just one 2k bro, u added 4k. So the answer would be k= -4
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I need proper answers of this question
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