if x^2+2x+1 = 0 then find. x + 1/x
Answers
Answered by
0
x^2+2x+1=0
x^2+x+x+1=0
x (x+1)+1 (x+1)=0
(x+1)(x+1)=0
therefore x=-1
x+1/x
-1+1/-1...... (value of x =-1)
-1-1=-2
x^2+x+x+1=0
x (x+1)+1 (x+1)=0
(x+1)(x+1)=0
therefore x=-1
x+1/x
-1+1/-1...... (value of x =-1)
-1-1=-2
Attachments:
Answered by
27
Solution:-
=> x² + 2x + 1 = 0
by mid term splitting.
=> x² + x + x + 1 = 0
=> x ( x + 1 ) + 1 ( x + 1 ) = 0
=> ( x + 1 ) ( x + 1 ) = 0
=> x + 1 = 0 or x + 1 = 0
we get x = - 1 from both
=> x = - 1
put x = - 1 in below
=> x + 1/x
=> - 1 + 1/- 1
=> - 1 - 1
=> - 2
Hence, x + 1/x = - 2
i hope it helps you.
Similar questions