If (x+2)(2x)(2x+3) are in A.P the value of x
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AP: x+2,2x,2x+3
a=x+2 d=2x-x-2=x-2
Now; a+2d =2x+3
x+2+2x-4=2x+3
3x-2=2x+3
x=5
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