Question

If (X+2)(2x-3)-2x^2+6/x-5=2,then the value of X is _____?

Answer 1

(x+2)(2x-3)-2x^2+6/x-5=2

x(2x-3)+2(2x-3)-2x^2+6/x-5=2

2x^2-3x+4x-6-2x^2+6/x-5=2

2x^2 with opposite sign gets cancelled

and -6 and +6 gets cancelled on same side of equal...

-3x+4x/x-5=2

x=2(x-5)

x=2x-10

x-2x=-10

-x=-10

negative sign gets cancelled

x=10...

here is your answer dude..... ☺