If x^2+2x+k is completely divisible by x-1,then find the value of k using division algorithm
Answers
Answered by
39
Hii ☺ !!
x - 1 = 0
x = 1
P ( x ) = x² + 2x + k
p (1) = 1² + 2 × 1 + k = 0
=> 1 + 2 + k = 0
=> k = -3
x - 1 = 0
x = 1
P ( x ) = x² + 2x + k
p (1) = 1² + 2 × 1 + k = 0
=> 1 + 2 + k = 0
=> k = -3
Answered by
16
Heyy mate ❤✌✌❤
Here's your Answer.....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
X - 1 = 0
X = 1.
p (x) = x^2 + 2x + k
p (1) =1 + 2 + k
= 3 + k
k = -3.
✔✔✔
Here's your Answer.....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
X - 1 = 0
X = 1.
p (x) = x^2 + 2x + k
p (1) =1 + 2 + k
= 3 + k
k = -3.
✔✔✔
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