"If x +2, 2x, x + 3 are three consecutive terms of an A.P. then find x
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Answered by
2
Given: (x + 2), 2x, (2x + 3) are three consecutive terms of an AP.
So, 2x – (x + 2) = (2x + 3) – 2x
2x – x – 2 = 2x + 3 – 2x
x – 2 = 3
x = 2 + 3 = 5
Answered by
1
Answer:
D = A2 - A1 and A3 - A2
2x - (x+2) = 2x+3 - 2x
X-2 = 3
x = 5
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