Question

If x/2=2y/3 and 2y=4. What is the value of 3x+y?

Answer 1

Answer:

the value of 3x+y is 10

x/2=2y/3

x/2=2y/3put y

x/2=2y/3put y 2y=4

x/2=2y/3put y 2y=4y=2

x/2=2y/3put y 2y=4y=2so,=2

x/2=2y/3put y 2y=4y=2so,=2x/2=4/3

x/2=2y/3put y 2y=4y=2so,=2x/2=4/33x=8

x/2=2y/3put y 2y=4y=2so,=2x/2=4/33x=8x=8/3

x/2=2y/3put y 2y=4y=2so,=2x/2=4/33x=8x=8/3then

3x+y

3*8/3+2

8+2

10

Answer 2

Given:-

• 2y = 4

To find:-

$\sf \dfrac{x}{2} = \dfrac{2y}{3}$

and 3x + y

Solution:-

2y = 4

Substituting the value of 2y in x/2 = 2y/3

$\sf \dfrac{x}{2} = \dfrac{2y}{3}$

$\sf \dfrac{x}{2} = \dfrac{4}{3}$

$\sf x = \dfrac{2 \times 4}{3} = \dfrac{8}{3}$

$\boxed{\sf x = \dfrac{8}{3}}$

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$\sf 2y = 4$

$\boxed{ \sf y=2}$

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Now , we will find the value of 3x + y

$\sf 3x + y$

$\sf \implies 3 \Bigg ( \dfrac{8}{3} \Bigg ) + 2$

$\sf \implies 8+ 2$

$\sf \implies 10$

Value of 3x + y is 10.

Hope it helps