Math, asked by siddharthshankar043, 10 months ago

If x=2√3+2√2 find: 1.1÷x 2. x+1÷x 3. (x+1÷x) square

Answers

Answered by Anonymous
18

Step-by-step explanation:

GIVEN,

x= 2√3+2

GIVEN the task,

1.

1÷x

Putting the value of x

1÷2√3+2

2.

x+1÷x

PUTTING THE VALUE OF X,

2√3+2+1÷2√3+2

1+1=2

3.

(x+1÷x)^2

(2√3+2+1÷2√3+2)^2

(1+1)^2

(2)^2

4

Answered by Anonymous
5

Answer:

given \\ x = 2 \sqrt{3}  + 2 \sqrt{2}  \\ 1)1 \div x \\ =  > 1 \div  2\sqrt{3}  + 2 \sqrt{2}  \\  =  > 1 \div 2 \sqrt{3}  + 2 \sqrt{2}  \times 2 \sqrt{3}  - 2 \sqrt{2}  \div 2 \sqrt{3}  - 2 \sqrt{2}  \\  =  > 2 \sqrt{3}  - 2 \sqrt{2}  \div 4(3) - 4(2) \\  =  > 2 \sqrt{3}  - 2 \sqrt{2}  \div 12 - 8 \\  =  > 2 \sqrt{3}  - 2 \sqrt{2} \div 4 \\  =  >  \sqrt{3 }   -  \sqrt{2}  \div 2

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