Math, asked by abhishekgajraj6, 9 months ago

If x=2+3√2, then find the value of x+1/2​

Answers

Answered by Anonymous
2

Answer:

\blue{\bold{\underline{\underline{Answer:}}}}

Answer:

\green{\tt{\therefore{Maximum\:height=26.67\:m}}}∴Maximumheight=26.67m

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

Step−by−stepexplanation:

\begin{lgathered}\green{\underline \bold{Given:}} \\ \tt: \implies Velocity \: at \: one \: fourth = 20 \: m/s \\ \\ \red{\underline \bold{To \: Find:}}\\ \tt: \implies Maximum \: height \: attained = ?\end{lgathered}

Given:

:⟹Velocityatonefourth=20m/s

ToFind:

:⟹Maximumheightattained=?

• According to given question :

\begin{lgathered}\tt \circ \: Let \: height \: be \: h \\ \\ \tt \circ \: Final \: velocity = 20 \: m/s \: at \: \frac{h}{4} \\ \\ \tt \circ \: Acceleration = - 10 \: {m/s}^{2} \\ \\ \bold{As \: we \: know \: that : } \\ \tt: \implies {v}^{2} = {u}^{2} + 2as \\ \\ \tt: \implies {20}^{2} = {u}^{2} + 2 \times ( - 10) \times \frac{h}{4} \\ \\ \tt: \implies 400 = {u}^{2} - 5h \\ \\ \tt: \implies {u}^{2} = 400 + 5h - - - - - (1) \\ \\ \tt \circ \: Final \: velocity = 0 \: m/s \: \: \: (For \: maximum \: height) \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies {v}^{2} = {u}^{2} + 2as \\ \\ \tt: \implies {0}^{2} = {u}^{2} + 2 \times ( - 10) \times h \\ \\ \tt: \implies 0 = {u}^{2} - 20h \\ \\ \tt: \implies {u}^{2} = 20h - - - - - (2) \\ \\ \circ \: \tt{Putting \: value \: of \: {u}^{2} \: in \: (1)} \\ \tt: \implies 20h = 400 + 5h \\ \\ \tt: \implies 15h = 400 \\ \\ \tt: \implies h = \frac{400}{15} \\ \\ \green{\tt: \implies h = 26.67 \: m} \\ \\ \green{\tt \therefore Maximum \: height \: attained \: is \: 26.67 \: m}\end{lgathered}

∘Letheightbeh

∘Finalvelocity=20m/sat

4

h

∘Acceleration=−10m/s

2

Asweknowthat:

:⟹v

2

=u

2

+2as

:⟹20

2

=u

2

+2×(−10)×

4

h

:⟹400=u

2

−5h

:⟹u

2

=400+5h−−−−−(1)

∘Finalvelocity=0m/s(Formaximumheight)

Asweknowthat

:⟹v

2

=u

2

+2as

:⟹0

2

=u

2

+2×(−10)×h

:⟹0=u

2

−20h

:⟹u

2

=20h−−−−−(2)

∘Puttingvalueofu

2

in(1)

:⟹20h=400+5h

:⟹15h=400

:⟹h=

15

400

:⟹h=26.67m

∴Maximumheightattainedis26.67m

Answered by zayaanshamsheer
1

Answer:

putting the value of x in x+1/2

2+3√2+1/2=2(2+3√2)/2+1/2

=4+6√2/2+1/2=5+6√2/2

therefore x+1/2=5+6√2/2

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