Question

if x=2/3+√7,then then the value of (x - 3)² is​

Answer 1

Answer:

7

Step-by-step explanation:

Rationalise the denominator

Then,

x=3-√7

put value of x in (x-3)^2

(3-√7-3)^2

(-√7)^2

7

Answer 2

Step-by-step explanation:

$x= \frac{2}{3+\sqrt{7} }\\x= \frac{2(3-\sqrt{7)} }{(3+\sqrt{7})(3-\sqrt{7}) } \\x= \frac{6-6\sqrt{7} }{(3)^{2}-(\sqrt{7}) ^{2} }\\x= \frac{6-6\sqrt{7} }{9-7}\\x= \frac{6-6\sqrt{7} }{2} \\\\</p><p>2 to be taken common, so :-\\x= 3-3\sqrt{7} </p><p>value of (x-3)^{2} \\(x)^{2} + (3)^{2} -2*x*3\\\\(3-3\sqrt{7}) ^{2} +9-6(3-3\sqrt{7})\\( (3)^{2}+(3\sqrt{7}) ^{2}-2*3*3\sqrt{7})+9-18+18\sqrt{7} \\(9+9*7-18\sqrt{7})-9+18\sqrt{7} \\9+63-18\sqrt{7} -9+18\sqrt{7} \\63\\(x-3)^{2} = 63$

hope it helps ;))))