If x=2/3+√7,then(x-3)^3 is
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Given that,
x=2/(3+√7)
x=2/(3+√7)×(3-√7)/(3-√7)
x=2(3-√7)/(9-7)
x=3-√7
Now,
(x-3)^3=(3-√7-3)^3
=(-√7)^3
=(-√7)^2×(-√7)
=7(-√7)
=-7√7
Hence (x-3)^3=-7√7
x=2/(3+√7)
x=2/(3+√7)×(3-√7)/(3-√7)
x=2(3-√7)/(9-7)
x=3-√7
Now,
(x-3)^3=(3-√7-3)^3
=(-√7)^3
=(-√7)^2×(-√7)
=7(-√7)
=-7√7
Hence (x-3)^3=-7√7
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