Question

if x=2/3 and x=-3 are roots of the quadratic equation ax^2+7x+b.
find the value of a and b...​

Answer 1

Answer:

Step-by-step explanation:

Refer picture :

Answer 2

Answer:

Step-by-step explanation:

 If x = 2/3, x = -3 are roots, then the eqn will be

    (x-2/3)(x-(-3))=0

 ⇒ (x-2/3)(x+3) = 0

 ⇒ x²-(2/3)x+3x-2 = 0

 ⇒ 3x²-2x+9x-6=0

 ⇒ 3x²+7x-6=0 is the required eqn.

Compare the eqn with ax²+7x+b=0

Therefore, a=3, b= -6

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