Math, asked by yashchauhan4133, 1 year ago

if x=2/3 and x=-3 are the roots of eq ax2+7x+b=0 find values of a and b

Answers

Answered by poojan
765
Basic point: If a,b are the roots of an eqn, then (x-a)(x-b)=0 be that quadratic equation.

 If x = 2/3, x = -3 are roots, then the eqn will be
     (x-2/3)(x-(-3))=0
 ⇒ (x-2/3)(x+3) = 0
 ⇒ x²-(2/3)x+3x-2 = 0
 ⇒ 3x²-2x+9x-6=0
 ⇒ 3x²+7x-6=0 is the required eqn.

Compare the eqn with ax²+7x+b=0

Therefore, a=3, b= -6

Answered by syedzeeshan899p4k4je
179

Here is the correct ans

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