if x=2/3 and x=-3 are the roots of eq ax2+7x+b=0 find values of a and b
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Substitute the values of x in the equation......... Then
4a+9b= -42
-27 a+ b = 21
Use elimination method to obtain answer
4a+9b= -42
-27 a+ b = 21
Use elimination method to obtain answer
Answered by
4
a x [2/3] sq + 7 x 2/3 + b = 0
4a/9 + 126 + 9b = 0
12a + 27b + 126 = 0
4a + 9b + 42 = 0 -----------------eq no 1
a[-3] sq + 7 x -3 + b =0
9a + b - 21 =0 ----------------------eq no 2
by eliminating methord, we can obtain answer
4a/9 + 126 + 9b = 0
12a + 27b + 126 = 0
4a + 9b + 42 = 0 -----------------eq no 1
a[-3] sq + 7 x -3 + b =0
9a + b - 21 =0 ----------------------eq no 2
by eliminating methord, we can obtain answer
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